Question

calcuate the energy and frequency of the radiation emitted when an electron jumps from n=2 to n=1 in an hydrogen atom. ​

Answer 1

Answer:

as we know E=13.6/n2 hence e2 -e1= 13.6/2square -13.6/1square

ans is-4.53 and frequency = hc/lamda.

for 1/lambda=R(1/n1square-1n2square)