calcuate the number of molecules of sulphur (SB) present in 16 g of solid sulphur
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Answer:
`3.76 xx 10^(22)` molecules
Explanation
Solution :
1 mole of solid sulphur (S8) = 8 × 32g = 256g i.e., 256g of solid sulphur contains = 6.022 × 1023 molecules
Then, 16g of solid sulpur contains `=6.022xx10^(23)//256=16` molecules
`= 3.76 × 10^(22)` molecules
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