Question

CALCUL RAPIDE
A+A=30
B+B=20
C+C=8
A+BxC=

Answer 1

A+B×C=15+10×4
=15+40
=55

Answer 2

A+BxC= 55 if A+A=30 , B+B=20 , C+C=8

Given:

• A+A=30
• B+B=20
• C+C=8

To Find:

• A+BxC=

Solution:

Step 1:

Solve for A

A + A = 30

=> 2A = 30

=> A = 15

Step 2:

Solve for B

B + B = 20

=> 2B = 20

=> B = 10

Step 3:

Solve for C

C + C = 8

=> 2C = 8

=> C = 4

Step 4:

Substitute values of A , B and C in A + B x C  and apply BODMAS

15 + 10 x  4

First Multiply the numbers

= 15 + 40

Then Add the numbers

= 55

Hence A+BxC= 55

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