Question

Calculate 103 X 107 using algebraic identities

Answer 1

Answer:11021

Step-by-step explanation:103x107

(100+3)(100+7)

Similar to (x+a)(x+b)=x²+(a+b)x+ab

So, =>100²+(3+7)100+(3x7)

=>10000+100x3+7x100+21

=>10000+300+700+21

=>11021 :)

Thank you hoped it helped you:)

Answer 2

Answer:

11021

Step-by-step explanation:

Concept

• Algebraic identities are algebraic equations that are valid for all values of variables in them. Polynomial factorization is also done with them. Algebraic identities are utilised in this way to compute algebraic expressions and solve various polynomials.

Find

algebric identities of 103*107

Solution

We know that $(x+a)(x+b)=x^{2}+(a+b) x+a b$

To split $103 \times 107$, we need a square that is easy to calculate.

Hence, $x=100, a=3, b=7$

$\therefore 103 \times 107=(100+3)(100+7)$

$=100^{2}+(3+7)(100)+(3)(7)$

$=10000+1000+21=11021$

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