Question

calculate(997)² using algebraic identities

Answer 1

hey dear your answer is here
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997^2

(1000-3)^2

1000^2-6000+9

1000000-6000+9

=994009

Answer 2

Heya ✋

Let see your answer !!!!

(997)^2

= (1000 - 3)^2

We know that

(a - b)^2 = a^2 + b^2 - 2ab

= (1000)^3 + (3)^2 - 2 × 1000 × 3

= 1000000 + 9 - 6000

= 1000009 - 6000

= 994009


Thanks :))))