calculate
a and b
effective capacitance between a and b
C1=C3=100πF
C2=C4=200πF
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Answer:
150πf
Explanation:
C1 and C2 are in parallel so C' = C1+C2, 100 +200=300πF
C3 and C4 are also in parallel C" = C3 + C4, 100+200 =300πF
After this C and C' are in series so 1/C = 1/C' +1/C"
1/C = 1/300 + 1/300
1/c = 2/300
C= 150πF
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