Question

calculate (a) molality (b) molarity (c) mole fraction of KI if the density of 20 (mass/mass) aqueous KI solution is 1.202 gmL

Answer 1

Answer:

Molality

w

w

%=20

100 gm solution has 20 gm KI

80 gm solvent has 20 gm KI

m=

1000

80

166

20

=1.51mol

Molarity

Volume =

d

m

⇒

1.2

20

=83.2

Molalrity =

83.2

.120×1000

=1.44 m

Mole fraction $$ = \dfrac{\dfrac{20}{166}}{\dfrac{80}{18} + \dfrac{20}{166}} $

Answer 2

Explanation:

calculate (a) molality (b) molarity (c) mole fraction of KI if the density of 20 (mass/mass) aqueous KI solution is 1.202 gmL