calculate
a) Total distance between AB, BC and CD
b)the distance covered between a to b ,b to c and c to d
c)acceleration in time intervals of 0to5 seconds , 5 to 15 seconds and 15 to 20 seconds
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Answers
Answered by
1
Answer:
Total distance covered=50+40+20=110 m
ED=BC-40m
AE=AB-CD
=50-20=30m
Total displacement =
40
2
+30
2
=50 m
Explanation:
Answered by
2
A force is an effort in the form of a pull or a push which tends to change the state of motion/rest, direction of motion or shape of the object acted upon.
Simply, its a push or a pull.
Data is not sufficient ig
Hi
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