calculate
a) Total distance between AB, BC and CD
b)the distance covered between a to b ,b to c and c to d
c)acceleration in time intervals of 0to5 seconds , 5 to 15 seconds and 15 to 20 seconds
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genivedaan06:
I think irs incomplete
Answers
Answered by
1
Answer:
Area under v-t graph gives the displacement (or distance) of the object during that period.
Thus distance traveled in first two seconds is equal to the area of triangle OAB.
Distance, S=
2
1
×10×2=10 m
Answered by
0
i think data is insufficient
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