Chemistry, asked by sujaySubramanian, 1 year ago

Calculate (a) wavenumber and (b) frequency of yellow radiation having wavelength 5800 Å.

NCERT Class XII
Chemistry - Main Course Book I

Chapter 2. Structure of Atom

Answers

Answered by mindfulmaisel
295

Wavenumber of the yellow radiation is \bold{1.72 \times 10^{6}\ \mathrm{m}^{-1}}

Frequency of the yellow radiation is \bold{5.17 \times 10^{14}\ \mathrm{sec}^{-1}}

Given:  

Wavelength =5800 \dot{\mathrm{A}}=5800 \times 10^{-10} \mathrm{m}

Wavenumber =\frac{1}{\text {wavelength}}

Hence plug the given values:

Wavenumber =\frac{1}{5800 \times 10^{-10} m}=1.72 \times 10^{6} m^{-1}

Frequency =\frac{C}{\text {wavelength}}

Here,

C = Speed of light =3 \times 10^{8}\ \mathrm{m} / \mathrm{sec}

Plug the given values:

Frequency =\frac{3 \times 10^{8}\ \mathrm{m} / \mathrm{sec}}{5800 \times 10^{-10}\ \mathrm{m}}

Frequency =5.17 \times 10^{14}\ \mathrm{sec}^{-1}

Answered by ssanskriti1107
1

Answer:

The frequency is 0.05\times10^{16} Hz and the Wave Number is 0.017\times10^{8} m^{-1}.

Explanation:

Wavelength of radiation = 5800\AA

                                         = 5800\times10^{-10} m

Frequency =  \frac{Speed\hspace{0.1cm}of\hspace{0.1cm} light}{Wavelength}

                   = \frac{3\times10^{-8}}{ 5800\times10^{-10}}

                  = 0.05\times10^{16} Hz

Wave Number = \frac{1}{Wavelength}

                        =  \frac{1}{5800\times10^{-10} }

                        = 0.017\times10^{8} m^{-1}

Hence, the frequency is 0.05\times10^{16} Hz and the Wave Number is 0.017\times10^{8} m^{-1}.

#SPJ2

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