Calculate abd and bdc
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bcd = 110 because opposite angles of cyclic quadrilateral are 180
then angle bdc= 180-(110+30) =40
angle adb = 90 because angle in the semicircle is 90....
now abd= 180-(90+70)= 20
then angle bdc= 180-(110+30) =40
angle adb = 90 because angle in the semicircle is 90....
now abd= 180-(90+70)= 20
gauri2001:
Angle bdc should be 60
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