Question

Calculate amount of oxalic acid required to obtained the 250 ml of semi molar solution
((COOH)22H2O)

Answer 1

$\underline{ \boxed{ \huge{ \bold{ \mathfrak{ \purple{Answer}}}}}} \\ \\ \dag \: \underline{ \boxed{ \bold{ \rm{ \pink{semi \: molar = 0.5 \: molar \: solution}}}}} \: \dag \\ \\ \implies \rm \: molarity = \frac{mass \times 1000}{molcular \: weight \times V_{ml}} \\ \\ \implies \rm \: 0.5 = \frac{weight \times 1000}{126 \times 250} \\ \\ \therefore \: \underline{ \boxed{ \bold{ \rm{ \orange{weight = 15.75 \: g}}}}} \red{ \star}$