Question

Calculate amount of water to be added to 1 L of soln of pH 2.1 so that pH increases to 4

Answer 1

We know,

pH=-log[H+]

=>[H+]=10^-2.1=9*10^-3 M

The [H+] should be made to 10^-4 M.

=>10^-4*(V+1)=9*10^-3*1

=>V=89 L