calculate amt of aminia formed of 56g nitrogen when reacts with oxygen
JunaidMirza:
Nitrogen when reacts with oxygen doesn’t form ammonia.
soory its hydrogen
now you can help
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We have 56 g of N₂
Molar mass of N₂ is 28 g/mol
Moles of N₂ = 56 g / (28 g/mol) = 2 mol
Balanced chemical equation for formation of Ammonia is as follows
N₂ + 3 H₂ → 2 NH₃
From above equation
1 mol of N₂ produces 2 mol of Ammonia
We have 2 mol of N₂
So, 4 mol of Ammonia is formed
Molar mass of Ammonia = 17 g/mol
Mass of Ammonia formed = 4 mol × 17 g/mol = 68 g
[Note: Mass of Hydrogen is not mentioned in the question. So I assumed it to be in excess]
Molar mass of N₂ is 28 g/mol
Moles of N₂ = 56 g / (28 g/mol) = 2 mol
Balanced chemical equation for formation of Ammonia is as follows
N₂ + 3 H₂ → 2 NH₃
From above equation
1 mol of N₂ produces 2 mol of Ammonia
We have 2 mol of N₂
So, 4 mol of Ammonia is formed
Molar mass of Ammonia = 17 g/mol
Mass of Ammonia formed = 4 mol × 17 g/mol = 68 g
[Note: Mass of Hydrogen is not mentioned in the question. So I assumed it to be in excess]
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