Question

calculate and compare electrostatic and gravitational force between two photons which are 10 m^2 apart. the value of g is 6.674 x 10^11 kg

Answer 1

ratio of electrostatic force and gravitational force between two protons is 1.23 × 10^36

photon is massless and no electric charge. so, electric force between two photons doesn't exist. gravitational force also negligible. then how we compare on them. if you proton in place of photon.

then follow the below given steps.

charge on proton = 1.6 × 10^-19 C [ in magnitude ]

mass of proton , M = 1.6726 × 10^-27 kg

distance between electron and proton = r

now , gravitational force between two protons,F = GM²/r²

= 6.67 × 10^-11 × (1.6726 × 10^-27)²/r²

= 18.65 × 10^-65/r²

electrostatic force of repulsion acting between two protons , F' = kq²/r²

= 9 × 10^9 × (1.6 × 10^-19)/r²

= 23.04 × 10^-29/r²

so, ratio of electrostatic force and gravitational force, F'/F = {23.04 × 10^-29/r²}/{18.65 × 10^-65/r²}

= 1.23 × 10^36

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Answer 2

$\huge\bold\purple{Answer:-}$

ratio of electrostatic force and gravitational force between two protons is 1.23 × 10^36

photon is massless and no electric charge. so, electric force between two photons doesn't exist. gravitational force also negligible. then how we compare on them. if you proton in place of photon.

then follow the below given steps.

charge on proton = 1.6 × 10^-19 C [ in magnitude ]

mass of proton , M = 1.6726 × 10^-27 kg

distance between electron and proton = r

now , gravitational force between two protons,F = GM²/r²

= 6.67 × 10^-11 × (1.6726 × 10^-27)²/r²

= 18.65 × 10^-65/r²

electrostatic force of repulsion acting between two protons , F' = kq²/r²

= 9 × 10^9 × (1.6 × 10^-19)/r²

= 23.04 × 10^-29/r²

so, ratio of electrostatic force and gravitational force, F'/F = {23.04 × 10^-29/r²}/{18.65 × 10^-65/r²}

= 1.23 × 10^36