Question

Calculate area of cross section of wire if its length is 1m resistance is 23 ohm and resistivity of the material is 1.84*10-6 ohm m

Answer 1

Answer:

The area of cross section of the wire is $\bold{8 \times 10^{-8} m^{2}}$

Explanation:

Given that

We have to calculate the “area of cross section” of the wire

So we have,

L=1 m

$\rho=1.84 \times 10^{-6} \text { ohm } m$

R =23 ohm

We now that

$\bold{\begin{array}{l}{\mathrm{R}=\frac{\rho L}{A}} \\ {\mathrm{A}=\frac{\rho L}{R}}\end{array}}$

Now let us substitute the known values in the above expression to find the area of cross section.

We get,

$A=1.84 \times 10^{-6} \times \frac{1}{23}$

By simplification we get,

$\begin{array}{l}{A=\frac{1.84 \times 10^{8}}{23}} \\ {A=8 \times 10^{-8} m^{2}}\end{array}$

Answer 2

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