Calculate area of triangle with height 12 CM and base 6 CM also calculate its perimeter ????
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Answered by
3
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☬ YOUR ANSWER ☬
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Area of triangle = 1/2×base* height
= 1/2 ×12 × 6
= 36 CM²
pErimeter = sum of all sides
=We have to calculate its so by phthogorean formula,,
⏩⏩⏩= √12² + 6²
⏩= √144 +36 =
⏩= 48cm
Peimeter = 48 +12 +6 = 66 cm
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☬ THANKS! @Brainlyconquerer ☬
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☬ YOUR ANSWER ☬
╘═════════════════════╛
Area of triangle = 1/2×base* height
= 1/2 ×12 × 6
= 36 CM²
pErimeter = sum of all sides
=We have to calculate its so by phthogorean formula,,
⏩⏩⏩= √12² + 6²
⏩= √144 +36 =
⏩= 48cm
Peimeter = 48 +12 +6 = 66 cm
╒══════════════════════╕
☬ THANKS! @Brainlyconquerer ☬
╘══════════════════════╛
Anonymous:
Don't Write Unnecessary things
Answered by
3
Hey Chika ❤
Here's ur answer-
area of ∆ = 1/2 × b × h
area of ∆ = 1/2 × 6 × 12
area of ∆ = 3 × 12
area = 36 cm²
Hence, area of triangle is 36 cm²
perimeter of ∆ = sum of all sides
Given,
b = 6cm
h = 12cm
[triangle here is an isoceles ∆ ]
So, finding the other side - we know that -
h² = b² + p²
h² = (3)² + (12)²
h² = 9 + 144
h² = 153
h² = √153
h² = 12.4
Hence, the other side measures = 12.4 cm
So, perimeter
= 12.4 + 12.4 + 6
=25.4cm
Hope it helps!
Here's ur answer-
area of ∆ = 1/2 × b × h
area of ∆ = 1/2 × 6 × 12
area of ∆ = 3 × 12
area = 36 cm²
Hence, area of triangle is 36 cm²
perimeter of ∆ = sum of all sides
Given,
b = 6cm
h = 12cm
[triangle here is an isoceles ∆ ]
So, finding the other side - we know that -
h² = b² + p²
h² = (3)² + (12)²
h² = 9 + 144
h² = 153
h² = √153
h² = 12.4
Hence, the other side measures = 12.4 cm
So, perimeter
= 12.4 + 12.4 + 6
=25.4cm
Hope it helps!
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