Question

Calculate atomicity of Mg (HCO3 )twice

Answer 1

The atomicity of $Mg(HCO_3)_2$ is 11.

• The atomicity of a compound is defined as the number of atoms present in the compound.
• The given compound is $Mg(HCO_3)_2$.
• This compound contains one Mg atom, two hydrogen atoms, two carbon atoms and six oxygen atoms.
• Hence the atomicity of this given compound is 1+2+2+6=11.

Answer 2

Answer:

The Atomicity of $Mg(HCO_3)_2$ is  11

Explanation:

Atomicity is defined as the total number of atoms present in the given compound. It can be determined by adding up the atoms of each element in the compound.

In $Mg(HCO_3)_2$, 1 atom of Magnesium, 2 atoms of Hydrogen, 2 atoms of Carbon, and 6 atoms of oxygen are present.

Atomicity $Mg(HCO_3)_2$ = No of atoms of Magnesium + No. of atoms of Hydrogen + No. of atoms of Carbon + No. of atoms of Oxygen

= 1+2+2+6=11

Therefore, the Atomicity of $Mg(HCO_3)_2$ is 11.