Question

calculate boiling point of 0.2m urea.Kb for water is 0.52K kg/mol.​

Answer 1

Explanation:

Tb−Tbo=i×kb×m

where,

T_bTb = boiling point of solution = ?

T^o_bTbo = boiling point of water = 100^oC100oC

k_bkb = boiling point constant  of water = 0.52^oC/m0.52oC/m

m = molality  = 0.2

i = Van't Hoff factor = 1 (for non-electrolyte)

Now put all the given values in the above formula, we get:

(T_b-100)^oC=1\times (0.52^oC/m)\times 0.2(Tb−100)oC=1×(0.52oC/m)×0.2

T_b=100.10^0CTb=100.100C

Therefore, the boiling point of 0.2 molar urea is 100.10^0C100.100C

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