Question

find the equation of the line perpendicular to the line 5x-3y+1and passing through the point (4,-3)​

Answer 1

Solution :

The given line is

5x - 3y + 1 = 0

Let, the line perpendicular to it be

3x + 5y + k = 0 .....(i)

Given that, (i) passes through (4, - 3). Then

3 (4) + 5 (- 3) + k = 0

or, 12 - 15 + k = 0

or, k = 3

∴ the equation of the required line is

3x + 5y + 3 = 0 ( Ans. )

Answer 2

Answer:

The line perpendicular to the given equation is assumed as such due to the rule of Eq for two perpendicular lines.

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