Question

calculate calculate total number of the electron present in 1.4 gram of Nitrogen gas

Answer 1

Molar mass of N2  = 28 g mol–1
Thus, 1.4 g of  N2 = 1.4/28
= 0.05 mol
= 0.05 x 6.023 x 1023
= 3.01 x 1023

1 molecule of N2 contains 14 electrons.
Hence,  3.01 × 1023 molecules of N2 contains
= 14 × 3.01 × 1023
= 4.214 × 1023 electrons
 Answer

Answer 2

Number of moles in the given weight of Nitrogen gas.

Number of moles = Given weight/molecular weight

= 1.4/28

=0.05 moles

1 mole of Nitrogen contains Avogadro number (6.023×(10)23) of Nitrogen molecules.

0.05 moles of Nitrogen contains =
0.05×6.023×(10)23

= 3.011×(10)22 molecules

1 molecule of Nitrogen contains 14 electrons

3.011*10(22) molecules contains = 3.011*10(22)*14

= 42.154×10(22)

= 4.215×(10)23 number of electrons

hope it will help you..