Question

calculate compound interest on 1000 over a period of 1 year at 10 per annum ,if interest is compound quarterly

Answer 1

CI= p(1+r/100)^n -p

p= 1000
r= 10%
n= 1x4=4

CI= 1000(1+10/100)^4 - 1000
    = 1000(1.1)^4 -1000
    = 1000(1.4641) - 1000
    = 1464.1-1000
    = 464.1

Answer 2

Answer:

$\answer$

Step-by-step explanation:

Answer:

Compound Interest = ₹ 103.8

Step-by-step explanation:

Given :

Principle (P) : ₹ 1,000

Interest rate (r) = 10 %

Time (n) = 1 year

To find :

Calculate compound interest

Solution :

$⇒ A = P (1 + \frac{r}{100} ) ^{4 \times n}(1+ </p><p>100</p><p>r</p><p> </p><p> ) </p><p>4×n$

$⇒ A = 1,000 (1 + \frac{10}{100} ) ^{4 \times 1}(1+ </p><p>100</p><p>10</p><p> </p><p> ) </p><p>4×1$

$⇒ A = 1,000 (1 + \frac{0.1}{4} ) ^{4 \times 1}(1+ </p><p>4</p><p>0.1</p><p> </p><p> ) </p><p>4×1$

⇒ 1,000 (1 + 0.025)⁴

⇒ 1,000 (1.1038)

⇒ 1,103.8

Amount = ₹ 1,103.8

CI = A - P

CI = 1,103.8 - 1,000

CI = 103.8

Therefore,

Compound Interest = ₹ 103.8