calculate cos(-theta) + sin(π-theta)/ sec(-theta)
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Answered by
1
Step-by-step explanation:
cos(-@) + sin(π-@) / sec(-@)
=> (cos@ + sin@)/sec@
=> cos@/sec@ + sin@/sec@
=> cos²@ + sin@cos@
=> cos@(1+sin@)
Answered by
0
Answer:
Answer is
Sin square(2) thete
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