Calculate de broglie wavelength assosciated with thermal neutrons at 27c
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Solution :
T=27+273=300KT=27+273=300K
Boltzmann's constant .
k=1.38×10−23Jmol−1k−1k=1.38×10−23Jmol−1k−1
Kinetic energy of neutron at absolute temperature
T is given by, E=32E=32kTkT
λ=h2mE−−−−√λ=h2mE
=h3mkT−−−−−√=h3mkT
λ=6.63×10−343×1.675×10−27×1.38×10−23×300−−−−−−−−−−−−−−−−−−−−−−−−−−−√λ=6.63×10−343×1.675×10−27×1.38×10−23×300
=1.45×10−10m=1.45×10−10m
This wave length is comparable to inter atomic spacing (1A∘)(1A∘) in a crystal , hence a high energy neutron beam should be first thermalized before using it for diffraction
T=27+273=300KT=27+273=300K
Boltzmann's constant .
k=1.38×10−23Jmol−1k−1k=1.38×10−23Jmol−1k−1
Kinetic energy of neutron at absolute temperature
T is given by, E=32E=32kTkT
λ=h2mE−−−−√λ=h2mE
=h3mkT−−−−−√=h3mkT
λ=6.63×10−343×1.675×10−27×1.38×10−23×300−−−−−−−−−−−−−−−−−−−−−−−−−−−√λ=6.63×10−343×1.675×10−27×1.38×10−23×300
=1.45×10−10m=1.45×10−10m
This wave length is comparable to inter atomic spacing (1A∘)(1A∘) in a crystal , hence a high energy neutron beam should be first thermalized before using it for diffraction
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