Calculate the molar solubility of pbcro4 in 1.6×10−3m k2cro4
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Pb CrO4 <=> Pb+2 & CrO4 -2
Ksp = [Pb+2] [CrO4]
Ksp = [5.3*10^-7 ] [5.3*10^-7 ]
Ksp = 2.8 e-13
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now to your question
Ksp = [Pb+2] [CrO4]
2.8 e-13 = [Pb+2] [1.1*10^-3 M]
[Pb+2] = 2.5 e-10 M
your answer
the molar solubility of PbCrO4 in
1.1*10^-3 M K2CrO4.is
2.5 X10^-10 M
Pb CrO4 <=> Pb+2 & CrO4 -2
Ksp = [Pb+2] [CrO4]
Ksp = [5.3*10^-7 ] [5.3*10^-7 ]
Ksp = 2.8 e-13
=================================
=====...
now to your question
Ksp = [Pb+2] [CrO4]
2.8 e-13 = [Pb+2] [1.1*10^-3 M]
[Pb+2] = 2.5 e-10 M
your answer
the molar solubility of PbCrO4 in
1.1*10^-3 M K2CrO4.is
2.5 X10^-10 M
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