calculate de broglie wavelength of electron of 1st bohr orbit
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●○we have
●○mvr=nh/2pi
●○r=a0 =.529A0
●○v=nh/2pimr
●○=2.18*10^6 m/s,here for first bohr orbit,n=1
debroglie wavelength =h/mv =6.6*10^-34/9.1*10^-31*2.18*10^6
=3.3A0
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●○we have
●○mvr=nh/2pi
●○r=a0 =.529A0
●○v=nh/2pimr
●○=2.18*10^6 m/s,here for first bohr orbit,n=1
debroglie wavelength =h/mv =6.6*10^-34/9.1*10^-31*2.18*10^6
=3.3A0
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