Question

Calculate degree of dissociation of 0.02 m acetic acid at 298k

Answer 1

Calculate the degree of dissociation of 0.02 M acetic acid at 298 K, given thatλCH3COOH=11.7ohm−1cm2mol−1λCH3COOH=11.7ohm−1cm2mol−1λ(CH3COO−)=40.9ohm−1cm2mol−1λ(CH3COO−)=40.9ohm−1cm2mol−1

λ∘(H+)=349.1ohm−1cm2mol−1λ∘(H+)=349.1ohm−1cm2mol−1

Answer 2

CH3COOH ==> CH3COO- + H+

i = 1 + alpha( degree of dissociation)


Now find alpha by osmotic pressure.
O.P = CRT = 0.02 × 0.0821 × 298 = 0.489

therefore alpha=1-0.489 =0.511