Physics, asked by samridhi227738, 2 months ago

Calculate density of 78 g of Iron piece with volume 10 cm
option
8.9g/ cm3 ,7.8g/ cm3​

Answers

Answered by Itsanshita
0

Answer:

Correct option is

C

6.8 N

Given that,

Volume of body V=10

−4

m

3

Density of iron, ρ

i

=7800kgm

−3

Density of water ρ

w

=1000kgm

−3

Weight in air,W

a

i

Vg=7800×10

−4

×10=7.8N

We know that,

Weight in water = weight in air – buoyancy force

W

w

=W

a

−ρ

w

Vg

W

w

=7.8−1000×10

−4

×10

W

w

=6.8N

Hence, the weight of body in water is 6.8 N

Answered by himanshisheoran4
0

Answer:

density = mass/ volume

Explanation:

Its unit is kg/m³

i) mass =78g

1000g=1kg

1g=1/1000kg

78g= 78/1000kg= 0.078kg

ii) volume 10cm³

100cm= 1m

1cm =1/100m

10cm=1/100×10= 1/10 m

= 0.1 m

density= mass/volume

0.078/0.1=0.78

HENCE DENSITY = 0.78KG/M³

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