Question

calculate density of niobium if atomic radius is 143.1 pm

Answer 1

$8.6g \: cm { }^{ - 3}$

Explanation:

For bcc, r=3–√4a or a=4r3=4×143.11.732pm =330.5 pm

ρ=Z×Ma3×N0=2×93(330.5×10−10)3×(6.02×1023)=8.6g cm−3

hope it helps