Question

Calculate distance and displacement in an object moving along the boundary of circular track diameter 10m and completes 4.5 rounds

Answer 1

Hii..
Here is your answer..

Solution:-
Diameter=10m
Radius=10/2
$= > 5m$
Distance covered in 1 round =Circumference of the circle=2πr
$= > 2 \times \frac{22}{7} \times 5 \\ = > \frac{220}{7}$
Now,
Distance covered when he completed 4.5 round is:-
$= > \frac{220}{7} \times 4.5 \\ = > 141.42$
Therefore,distance covered=141m (approx)

Since when he completed 4.5 round the must be at the opposite side of starting point and Acceleration is the shortest distance between initial and final position.

Here shortest distance is diameter of the circle since he is opposite side of starting point.

Hence,Displacement =10m

Hope it helps uh...✌️✌️✌️

Answer 2

Hii..

Here is your answer..

Solution:-

Diameter=10m

Radius=10/2

= > 5m

Distance covered in 1 round =Circumference of the circle=2πr

= > 2 \times \frac{22}{7} \times 5 \\ = > \frac{220}{7}

Now,

Distance covered when he completed 4.5 round is:-

= > \frac{220}{7} \times 4.5 \\ = > 141.42

Therefore,distance covered=141m (approx)

Since when he completed 4.5 round the must be at the opposite side of starting point and Acceleration is the shortest distance between initial and final position.

Here shortest distance is diameter of the circle since he is opposite side of starting point.

Hence,Displacement =10m

Hope it helps uh...✌️✌️✌️

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