Physics, asked by SHARONNELSON, 1 year ago

Calculate electric energy consumed when 3bulbs of 100w, 2fans of 60w,television of 100w is used 6hours daily in a month of 30 days .if electric energy cost ₹3 per unit, calculate complete expenditure for the month

Answers

Answered by Ravenclaw1
0
Hey friend here's your answer
Total power=3×100+2×60+100watt
=520watt
Now, energy consumed in 30 days
=520×6hour/day×30days
=93600wh
So,cost of energy=93600×₹3
=₹280800
Hope it helps u.☺️
If it helped u make it the brainliest.
Answered by ABHINAVrAI
0
Plzzz SUBSCRIBE my YouTube channel (BanarasiiiINDIA) if this answer is helpful for you.This is my YouTube channel Link-https://www.youtube.com/channel/UC27NLinpXVunbzVQ0vdHabQ
Energy consumed by 1 electric bulb = power of the bulb ⨯ Time
Energy consumed by 3 electric bulb of 100 w in 30 days= 100 w⨯30days⨯6hrs⨯3bulbs
=54000watt-hour=54Kw-hour

Energy consumed by 2 fans of 60watt in 30days = 60×30days×6hrs×2fans
=21600w=21.6Kw-hour

Similarly,
Energy consumed by 1 television of 100 w in 30 days=100w×30days×6hrs×1 t.v.
=18000watt=18Kw-hour

Thus,
Total energy consumed=(54+21.6+18)Kw-hour
=93.6Kw-hour

Cost of 1Kw-hour=Rs.3
Cost of 93.6 Kw-hour=3×93.6
=Rs.280.8

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