Calculate emf of following
Cus/cu2aq//Ag+aq/Ags
Answers
Answered by
1
Answer:
Hope it helps you.....(✿◕‿◕✿)
Explanation:
E°anode = 0.41
E°cathode = 0.80
E°cell = Ecathode - E°anode
E°cell = 0.80 − (0.41) = 0.39V
Please mark as brainliest if it really helps you....❤❤❤
Similar questions
Math,
4 months ago
Geography,
4 months ago
Science,
4 months ago
English,
8 months ago
Social Sciences,
8 months ago
Physics,
1 year ago
Social Sciences,
1 year ago