Chemistry, asked by jsjatin9546, 8 months ago

Calculate emf of following
Cus/cu2aq//Ag+aq/Ags

Answers

Answered by Anonymous
1

Answer:

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Explanation:

E°anode = 0.41

E°cathode = 0.80

E°cell = Ecathode - E°anode

E°cell = 0.80 − (0.41) = 0.39V

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