Chemistry, asked by ShUbH3136, 1 year ago

Calculate emf of the cell of reaction between silver and nickel

Answers

Answered by Anishklegend
3

Answer:

objective is to study the variation of cell potential of Zn│Zn2+ ││Cu2+│Cu cell with change in the concentration of electrolytes (CuSO4 and ZnSO4) at room temperature.

In aqueous solutions at 25 °C2e– + Hg2+ (aq) Hg (l) E° = 0.86 V

In aqueous solutions at 25 °C2e– + Hg2+ (aq) Hg (l) E° = 0.86 V2e– + I2 (s) 2 I– (aq) E° = 0.54 V

In aqueous solutions at 25 °C2e– + Hg2+ (aq) Hg (l) E° = 0.86 V2e– + I2 (s) 2 I– (aq) E° = 0.54 V2e– + 2 H+ (aq) H2 (g) E° = 0 V

oxidation Zn(s)Zn2+(aq) + 2e– E° = 0.763 Vreduction 2 [ 1 e– + Ag+(aq) Ag (s) ] E° = 0.337 Vsumnet Zn(s) + 2 Ag+(aq) 2 Ag(s) + Zn2+(aq) E° = 1.100 V

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