Question

Calculate emf of the following cell at 298K
Zn/Zn?"(10^M) || Cu2+(10²M)/Cu
en E 7n/Zn2+ = -076V Ecu?"cu = +0.34V​

Answer 1

Answer:

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Explanation:

reaction. Zn/Zn2+//Cu2+/Cu. EMF of cell =E cathode-E anode. =+34V--0.76V=1.10V