calculate energy of photons having wavelength 3000 A° in joules , electron volt and kilojoules/ mol
Answers
Answered by
4
Answer:
energy of photon is 6.63×10^-19 Joule
Attachments:
Answered by
3
Energy of photon = 12400/3000 ev/atom
= 4.133 ev/atom
= 4.133 × 1.6 ×10^-19 J/atom
= 6.61 × 10^-19 J/atom
= 6.61 × 10^-19 × 6.023× 10^23/10^3. KJ/mole
= 398.12 KJ/mol
Similar questions