calculate enthalpy change (in kcal) in adiabatic compression of 5 moles of ideal triatomic non linear gas against a constant external pressure of 2atm starting from initial pressure of 1 atm and initial temperature 300k.Given: R= 2cal/mol.K.
Answers
Answered by
1
work done =∆U
∆U=fnRT/2
=>375 L-atm
∆H=∆U+ ∆PV
∆H=375+(2V2-62.5)
375=5*3*(T-300)
T2=325
v2=78.125L
∆H=468.75L-atn
akhileshkumard38:
∆U=fnRT/2
How
∆U=nCv∆T
And how ∆H=375+(2V2-62.5)
keep Cv=(f/2)R
sorry keep∆H=∆U*Y
Y=gamma=4/3
the answer is 500
i used ∆H=∆U +∆PV
Similar questions