Question

Calculate enthalpy of formation of c2h6 given yhe enthalpy of combustion of c2h4,c2h6 and h2 are -140kj/mol,-1550 kj/mol, and -286kj/mol respectively

Answer 1

The enthalpy of formation of $C_2H_6$ is 1124 KJ/mol .

The given equation of reaction is :

$C_2H_4+H_2\ -->C\ _2H_6$

We know ,

Enthalpy of formation of $C_2H_6$ is :

$E=\Delta H_{combustion(C_2H_4)}+\Delta H_{combustion(H_2)}-\Delta H_{combustion (C_2H_6)$

Putting all given values we get :

$E=(-140)+(-286)-(-1550)\ KJ/mol\\\\E=1124\ KJ/mol$

Hence , this is the required solution .

Learn More :

Thermochemistry

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