Calculate Eocell for the reaction:AgCl(s) + NO(g) → Ag(s) + Cl-(aq) + NO3-(aq) (in acidic solution).
The reduction potential for nitrate(aq) to give NO(g) is +0.96 V and for AgCl(s) it is +0.22 V.
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Explanation:
Hey, here is your answer:-
-0.74
Let's consider the following redox reaction.
AgCl(s) + NO(g) → Ag(s) + Cl⁻(aq) + NO₃⁻(aq)
We can identify the oxidation and reduction half-reactions.
Reduction (cathode): 1 e⁻ + AgCl(s) → Ag(s) + Cl⁻(aq)
Oxidation (anode): 2 H₂O(l) + NO(g) → NO₃⁻(aq) + 4H⁺(aq) + 3 e⁻
The standard cell potential (E°) is equal to the difference between the standard reduction potential of the cathode and the standard reduction potential of the anode.
E° = E°red,cat - Ered,an = 0.22 V - 0.96 V = -0.74 V
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