Question

calculate
If the normal pushing force of 25 LBS is required to push a wheel chair on a level floor for 160 lbs patient, calculate the pushing force of the wheelchair carrying 160 LBS weight when the ramp angle is 20 degrees.​

Answer 1

Answer:

pushing force is 152.41LBS

Explanation:

i solved this one by resolving force components along x and y axis

Answer 2

Pushing force is 78 lbs

Explanation:

On level ground, the normal force Fn=160 lbs, and the frictional force Ff=25 lbs. Therefore the coefficient of friction μ is:

μ=Ff / Fn=25 / 160=0.1563

On a 20∘ ramp, the normal force is decreased, and therefore frictional force Ff and gravitational force down the ramp Fg are:

Ff = μFn = (0.1563)(160cos20∘) = 23.49 lbs

Fg= 160sin20∘ = 54.72 lbs

Therefore the total force Fnet required to push the chair is:

Fnet = Ff + Fg = 23.49+54.72

= 78.21 lbs