Question

Calculate KB for water latent heat of vaporization for water is 540 cal per gram

Answer 1

Solution

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Correct option is

A

26 cal.K

−1

mol

−1

Solution:- (A) 26cal/mol−K

As we know that,

ΔS=

T

ΔH

ΔH=540cal/g

Mol. wt. of water =18g

ΔH

(per mole)

=ΔH

(per gm)

×Mol. wt.

ΔH

(per mole)

=540×18=9720cal/mol

Now, as we know that,

ΔS=

T

ΔH

Given T=100℃=(273+100)=373K

∴ΔS=

373

9720

=26cal/(mol.K)

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