Calculate kinetic energy of 2moles of nitrogen2 at 27 degree Celsius
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Kinetic energy of the ideal gas can be calculated as
Kinetic energy = {3*n*R*T} / 2
where,
n = number of moles
R = gas constant
T = temperature in kelvinKinetic energy of the ideal gas can be calculated as
here no of moles is 2
the value of R{universal gas constant} is=8/314= 0.0821
and T = 27 + 273 (to convert celsius to kelvin, add 273)=300.
kinetic energy=3*3*0.0821*300/2=110.835 joules
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