Question

Calculate kinetic energy of 5 moles of nitrogen at 27 degree Celsius

Answer 1

First of all, let's assume the N2 gas behave as an ideal gas, then the kinefic therory of gases is defined as K.E = 3.R.T/2.n, where R is the universal gas constant, T is the temperature of a gas and n is the number of moles. K.E can be calculated; K.E = [(3 x 8.3145 J/mol.K x (127 + 273)K] / 2 x 4 mol = 1247.175 Joules. The kinetic energy of 4 moles of N2 at 400 K (at 127 C) is 1.25 kJ (1247.175 J).