Question

calculate kinetic energy of 5 moles of nitrogen at 27°C

Answer 1

Kinetic energy of the ideal gas can be calculated as 

Kinetic energy = {3*n*R*T} / 2
where, 
n = number of moles
R = gas constant
T = temperature in kelvin

We have above is, n = 5 moles of N
R = 8/314, 
and T = 27 + 273 (to convert celsius to kelvin, add 273)=300. 

Kinetic energy = {3*5*8.314*300} / 2
= 18,706.05 joules or 18.706 kj

Hope this helps. If yes, please mark as Brainliest. 

Answer 2

Kinetic energy of the ideal gas  is 18.706 kilo Joule

Explanation:

Kinetic energy is defined as a form of energy where an object or a particle has by reason of its motion.

Here if work, transfers energy, and this is done on an object by applying a net force, then the object speeds up and thereby gains kinetic energy.

The kinetic energy of the ideal gas can be calculated as

Kinetic energy = {3×n×R×T} / 2

where,

n = number of moles

R = gas constant

T = temperature in kelvin

We have above is, n = 5 moles of N

R = 8314,

and T = 27 + 273 (to convert celsius to kelvin, add 273)=300.

Kinetic energy =[3×5×8.314×300]/2

= 18,706.05 joules or 18.706 kilo Joule

Kinetic energy of the ideal gas  is 18.706 kilo Joule

#SPJ6