if A=90degree state that sinB+sinC=/2
shriprateek:
your question is not clear
make it clear
Answers
Answered by
1
In a triangle if A = 90 deg, then B+C = 90 deg.
So Sin B = Cos C.
As angle 0< C < 90 1 < Cos C + Sin C < √2
let P = cos C + sin C
P² = 1 + 2 Sin C Cos C
= 1 + Sin 2 C
So 1 < P² < 2
Hence 1 < Sin B + Cos C < √2
So Sin B = Cos C.
As angle 0< C < 90 1 < Cos C + Sin C < √2
let P = cos C + sin C
P² = 1 + 2 Sin C Cos C
= 1 + Sin 2 C
So 1 < P² < 2
Hence 1 < Sin B + Cos C < √2
click on thanks link above please... select brainliest answer
i think the root as slash
so i was not clear
Similar questions