calculate kinetic energy, potential energy, total energy, binding energy of an artificial satellite of mass 200kg orbiting at hight 3600km above earth surface
Answers
Explanation:
Values given in question,
mass of earth M = 6×10^24 Kg
mass of satellite m = 2000 kg
radius of earth R = 6400 Km
height of satellite from earth surface h = 3600 km
radius of circular orbit of satellite r = (R+h)= 10000 Km
Now you should know that expression of energy's
Kinetic energy of satellite KE = GMm/2r
putting values in equation
Kinetic energy of satellite = given in image
Kinetic energy of satellite KE = 40.09*10^9 J
Now Potential energy of satellite PE = GMm/r
from question taking values
Potential energy of satellite PE = given in the image
Potential energy PE = -80.09*10^9 J
total energy of satellite TE = Kinetic energy of satellite + Potential energy of satellite
TE = KE + PE
total energy of satellite TE = -40.09*10^9 J
here negative sign show that satellite bounded with some force which we know as gravitational force so we are not taking negative sign in our answer.
total energy of satellite TE = 40.09*10^9 J
Binding energy of satellite BE = (energy of satellite at infinity distance) - (enrgy of satellite in earth orbit)
there is no force at infinity distance on satellite, so energy of satellite at infinity distance is Zero
Binding energy of satellite BE = (-GMm/2r)
BE = given in the image
BE = 40.09*10^9 J
Binding energy is equal to the total energy of satellite.
