Question

Calculate length of second pendulum at a place where acceleration due to gravity is 9.8 ms
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Answer 1

Answer:

Time period of pendulum is:

T=2πgl

l=4π2T2g

l=4×π24×9.8

l=0.993m=99.3m

l= length of pendulum 

g= 9.8m/s

T = Time period of seconds pendulum =2s

Answer 2

Answer:

1m

Step-by-step explanation:

seconds pendulum has time persiod=2 sec

2=2pi root(l/g)

4=39.47l/9.8

l=0.99m or 1m

FACT : length of seconds is 1m only

THANKS :)