Question

Calculate magnetic moment fe2+ion z=26

Answer 1

Answer: 4.9 BM

Explanation:

Electronic configuration of Fe with atomic number = 26

$Fe:26:[Ar]3d^64s^2$

$Fe^{2+}:23:[Ar]3d^6$

The number of unpaired electrons in $Fe^{2+}$ is 4

Formula used for magnetic moment :

$\mu=\sqrt{n(n+2)}$

where,

$\mu$ = magnetic moment

n = number of unpaired electrons

Now put all the given values in the above formula, we get the magnetic moment.

$\mu=\sqrt{4(4+2)}=4.9BM$

Therefore, the magnetic moment is 4.9 BM

Answer 2

Answer:

Explanation:

In Fe2+,no of unpaired electrons=4

Magnetic moment=✓n(n+2), where n is number of unpaired electrons.

So, Magnetic moment=✓24BM, hope you understood.