Calculate mass for 9.033 *1024 molecules of CO2
Answers
Answer:
660gm
Explanation:
We know,
(Mass)/(Molar mass) =Moles
And
Moles= (No. of particles)/(6.022×10^23)
=>Moles= (9.033×10^24)/(6.022×10^23)
=>Moles=30/2=15 moles
Molar mass of CO2=12+(16×2)
=>44 amu
So mass=moles×molar mass
=>Mass of CO2=(15×44) gm
=>Mass = 660gm
Hope it helps...
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Answer:
Explanation:
VOLUME
⇅
×22.4 L↑ ↓ ÷ 22.4 L
→÷ GAM/GMM ← ÷ 6.022×10∧23
MASS ⇔ MOLES ⇔ PARTICLES
←× GAM/GMM →× 6.022×10∧23