Calculate mass of 0.5 mole of sugar (C12H22O11)
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Answered by
26
the Mass of C = 12u mass of H = 1u mass of O = 16u
amu of sugar =( 12×12) + (1×22)+ (16×11)
=144 + 22 + 176 = 342u
molar mass = 342 gram
mass = no. of moles × molar mass = 0.5 × 342 = 171 gram
amu of sugar =( 12×12) + (1×22)+ (16×11)
=144 + 22 + 176 = 342u
molar mass = 342 gram
mass = no. of moles × molar mass = 0.5 × 342 = 171 gram
Answered by
3
Answer:
the Mass of C = 12u mass of H = 1u mass of O = 16u
amu of sugar =( 12×12) + (1×22)+ (16×11)
=144 + 22 + 176 = 342u
molar mass = 342 gram
mass = no. of moles × molar mass = 0.5 × 342 = 171 gram
Explanation:
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