Question

Calculate mass of 60% of H2SO4 required to decompose 50g of chalk CaCO3

Answer 1

1 mole of H2SO4 reacts with 1 mole of CaCO3.

Whereas mole=mass/molar mass

molar mass of CaCO3= 40+12+48=100 

therefore the moles =50/100 =0.5 moles

Hence the moles of the H2SO4 required to decompose the chalk= 0.5moles

 mass=molesx molar mass
therefore mass of H2SO4= 0.5x(2+32+64)
                                             = 49g

If 100% H2SO4 =49
then 60% H2SO4= 49x60/100
                               =29.4g


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